solve by substitution


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Question 2
Question: Show that the lines 3x - y - 6 = 0, 4x - y - 7 = 0 and 2x - y - 5 = 0 are concurrent. Answer: Given lines are Solving (i) and (ii) for x and y, we get The point of intersection is (1,-3). Now substituting x = 1 and y = -3 in the LHS of (iii), we get ..
Suggested answer:
= (14 - 12) - (7 - 3) + (4 - 2) = 2 - 4 + 2 = 0 The system may have infinite number of solutions or no solution. Put x = k in (1) and (2) and solve y + z = 6 - k 2y + 3z = 14 - k. Solving the above two equations, we have z = k + 2 and y = 4 - 2k When x = k, substitut..
3rd Method:
We can also solve the problem by substituting and get the same result. If a : b = c : d, then prove that Let or a = bk. Similarly, c = dk LH..
Simultaneous Equations-Method of Elimination
Method of Elimination - Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6y = 8 6y = 8 - 20 6y = -12 y = ..
Summary
The following are the steps to solve a system of linear equations using Cramer's rule. Step 1: Find the value of the determinant Step 2: If D 0, then the system has unique solution, given by Where D 1 , D 2 and D 3 are the determinants obtained from D by replacing respectively the first c..
Matrices and Determinants Summary
The following are the steps to solve a system of linear equations using Cramer's rule. Step 1: Find the value of the determinant Step 2: If D 0, then the system has unique solution, given by Where D 1 , D 2 and D 3 are the determinants obtained from D by replacing respectively the first c..
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