solve each system by substitution

Solve the system by substitution. 4 x + y = 5 - 16 x - 4 y = - 20 => (20.3, -76.2) or no solution or infinite solutions or (1, 1)..

Solve the system by substitution: 2 x + 6 y = 8 5 x = - 15 y + 25 => (3, 3) or No solution or Infinite solution or (15, 0)..

Solve the system by substitution: 3 x - y = 3, -6 x + 2 y = -6 => No solution or Infinitely many solutions or (2, 3) or (1, 0)..

Solve the system by substitution: 10 x + 10 y = 100 12 x = - 12 y + 108 => (100, 0) or No solution or (100, 10) or {( x , y ): 10 x + 10 y = 100}..

Solve the system of equations by substitution: 2 x - y = 10, x - z = - 1, and y = - 9 => x = 1 2 , y = -9, z = -3 or x = 1 2 , y = -9, z = 3 2 or x = - 1 2 , y = 9, z = 1 or x = -..

Solve the linear system by using the substitution method and find the number of solutions. 3 x + y = -10 6 x - 5 y = -55 => Infinitely many solutions or Exactly one solution or No solution or None of the above..

Solve the system of equation by substitution: 3 x - y + 2 z = - 2, y + 3 z = 3, and 2 z = 4 => x = -3, y = 3, z = 2 or x = 3, y = -3, z = 2 or x = -3, y = 3, z = -2 or x = -3, y = -3, z = 2..

Use the substitution method to solve the linear system. 59 x + 15 y = 180 x - 5 y = 2 => (- 3, 1 5 ) or (3, 1 5 ) or (3, - 1 5 ) or (- 3, - 1 5 )..

Identify the equation wherein you would isolate a variable easily so that substitution method can be used to solve the linear system. 4 x + 7 y = 1 [Equation 1] x - 3 y = - 2 [Equation 2] => Equation 1 or Equation 2 or Both Equation 1 and Equation 2 or Neither Equation..

Choose the equation wherein you would isolate a variable easily so that substitution method can be used to solve the linear system. - x + y = 4 [Equation 1] 3 x - 6 y = -15 [Equation 2] => Neither Equation 1 nor Equation 2 or Equation 1 and Equation 2 or Equation 1 or ..