solve intermediate algebra problems online

The mathematical concept of a function expresses the intuitive idea of deterministic dependence between two quantities, one of which is viewed as primary (the independent variable, argument of the function, or its "input") and the other as secondary (the value of the function, or "output"..

Question 1 - Question: Solve the following equation: 3(x-1)=8 Answer: 3(x-1)=8 3x-3=8 3x=8+3 3x=..

Simultaneous Equations - Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, y = 0. Similar..

The process of finding the value of the unknown quantity for which the equation is true, is called solving the equation. The value so found is called the root or solution of the equatio..

Function Solved Examples - The arrow diagram represents a relation from set A to set B. (i) Represent the relation in roster form. (ii) Is this relation a function? Give reason for your answer. (i) {(1, 2), (2, 4), (5, 2), (3, 10), (4, 10)} (ii) Yes it is a function. Every first element i..

Here is a list of problems solved using the identities of limits, standard limits, limits theorem explained above....

Solve the following Systems of linear equations : 1. If one number is thrice the other and their sum is 60, find the numbers. 2. Find the fraction which becomes 1/2 when the denominator is increased by 5 and is equal to 1/3 when the numerator is diminished by 4..

Two inequalities, containing the same unknowns, are called equivalent, if they are valid at the same values of the unknowns. The same definition is used for the equivalence of two systems of simultaneous inequalities. Solving of inequalities is a process of transition from one inequ..

Solving two equations simultaneously means to find the common solution of both the equations, i.e., a solution which satisfies both the equations. (Such a common solution, if it exists, can be shown to be unique..

(x + a)(x + b)(x + c)(x + d) = 0 In such equations, if the sum of any two constants a, b, c, d is equal to sum of the other two, then such pairs are multiplied and solve them if a+b = c+d = m then, Now put x 2 + mx = t then, (t + ab)(t + cd) + k = 0. This can be solved for t and..