solve the equation 223 = 4 and express the solution as a mixed fraction.

Solve the equation x - 4 4 5 = 6 and express the solution as a mixed fraction. => 5 5 7 or 10 4 5 or 9 1 5 or 9 1 3..

Solve the equation x - 4 2 3 = 3 and express the solution as a mixed fraction. => 7 or 6 1 2 or 7 2 3 or 5..

Express the model as a mixed number. => 1 2 or 1 1 4 or 1 3 2 or 1 1 2..

Express the improper fraction 11 4 as a mixed fraction. => 2 3 4 or 2 1 4 or 2 3 5 or 2 1 2..

Express the improper fraction 23 5 as a mixed number. => 4 2 5 or 4 4 5 or 4 3 5 or None of the above..

Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise in temperature = (840 JK - 1 ..

In the resulting solution, [Ca + + ] = 0.0025M. [C 2 O 4 2 - ] = 1 x 10 - 7 M. [Ca + + ][C 2 O 4 2 - ] = 0.0025 x 10 - 7 = 2.5 x 10 - 1 0 This is less than the solubility product of calcium oxalate. Thus, precipitation of calcium oxalate does not occur. ..

The degree of hardness of water is defined as the number of parts by mass of calcium carbonate, equivalent to various calcium and magnesium present in one million parts of mass of water. It is expressed in ppm. Now, 10 6 g of water contains CaCO 3 = 44 mg By definition, 1 mol of CaCO 3..

The given problem is solved in the following table. Empirical formula = N 2 H 8 S 1 O 4 = N 2 H 8 SO 4..

The required D H is The given equations are: Multiply equation (i) and (ii) by 3 and add them. Now subtract equation (iii) and subsequently add equation (iv) from the resulting expression. D H = 3 D H 1 + 3 D H 2 - D H 3 - D H ..