Steps
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..Steps:
The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Sh..
Step 1
For a differentiable function f (x), find f '(x). Equate it to zero. Solve the equation f '(x) = 0 to get the Critical values of f (x..
Step 1:
Since the two decision variable x and y are non-negative, consider only the first quadrant of xy- plane Draw the line ax + by = c ...(1) For each constraint, the line (1) divides the first quadrant in to two regions say R 1 and R 2 , ..
Since the two decision variable x and y are non-negative, consider only the first quadrant of xy- plane Draw the line ax + by = c ...(1) For each constraint, the line (1) divides the first quadrant in to two regions say R 1 and R 2 , ..Step 1
Separate the equation into two half reactions: The oxidation number of various atoms are shown below: In this case, chromium undergoes reduction, oxidation number decreases from +6 (in Cr 2 O ) to +3 (in Cr 3 + ) Fe 2 + (O.N. = +2) changes to ..
Separate the equation into two half reactions: The oxidation number of various atoms are shown below: In this case, chromium undergoes reduction, oxidation number decreases from +6 (in Cr 2 O ) to +3 (in Cr 3 + ) Fe 2 + (O.N. = +2) changes to ..Step 1:
Find a value of the variable x for which the value of x 2 + 3x - 4 is equal to 0. Let x =1, Then, f(1) = (1) 2 + 3(1) - 4 = 0..
Find a value of the variable x for which the value of x 2 + 3x - 4 is equal to 0. Let x =1, Then, f(1) = (1) 2 + 3(1) - 4 = 0..Step 1
Production of SO 2 from pyrites or sulphur..
Production of SO 2 from pyrites or sulphur..Step 2:
Find the co-ordinates of each vertex of the feasible region. These co-ordinates can be obtained from the graph or by solving the equation of the line..
Step 2:
The first term in (1 + x) n is always 1..
Step 2:
If log (sin C) comes out as positive, sin C would have to be greater than 1 and there is no solutio..
Result
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