solving complement of a set

Let U be a universal set, A be any subset of U, then the elements of U which are not in A i.e., U - A is the complement of A w.r.t. U is written as A' = U - A = A c ..

The Operations on Sets are: Union of sets, Intersection of sets, Disjoint sets, Difference of two sets (Relative complement), Symmetric Difference of two sets, Complement of a set..

Graphical Method of Solution of a Linear Programming Problem - So far we have learnt how to construct a mathematical model for a linear programming problem. If we can find the values of the decision variables x 1 , x 2 , x 3 , ..... x n , which can optimise (maximize or minimize) the objective func..

The arrow diagram represents a relation from set A to set B. (i) Represent the relation in roster form. (ii) Is this relation a function? Give reason for your answer. (i) {(1, 2), (2, 4), (5, 2), (3, 10), (4, 10)} (ii) Yes it is a function. Every first element is mapped a..

Argument - An argument is a statement which assets that a given set of n compound statements p 1 ,p 2 ,..........p n yield another compound statement Q. This is denoted by where p 1 ,p 2 ,..........p n are called hypotheses or premises or assumptions. The compound statement Q is called th..

Solve and graph the solution set of - 58 < 3 x + 2 ≤ 17. => Graph C or Graph D or Graph A or Graph B..

Solve the inequality ( x - 3) 2 > 0 and choose a graph for the solution set. => { x : x > 3}, Graph 1 or { x : x < 3}, Graph 2 or { x : x ≥ 3}, Graph 3 or { x : x < 3 or x > 3}, Graph 4..

Solve the inequality ( x - 3) 2 > 0 and choose a graph for the solution set. => { x : x > 3}, Graph 1 or { x : x < 3}, Graph 2 or { x : x ≥ 3}, Graph 3 or { x : x < 3 or x > 3}, Graph 4..

Solve the inequality x 2 - 25 > 0 and identify the graph the solution set on a number line. => { x : x ≤ - 5 or x ≥ 5}, Graph 1 or { x : x < - 5 or x > 4}, Graph 2 or { x : - 5 < x < 5}, Graph 3 or { x : x < - 5 or x > 5}, Graph 4..

Solve 3 x > - 15 and 9 x < 27 and graph the solution set if it is not the empty set. => Graph C or no solution or Graph A or Graph B..