solving one step equations


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To maximise Z draw a line parallel to ax + by = k and farthest from the origin. This line should contain at least one point of the feasible region. Find the coordinates of this point by solving the equations of the lines on which it lies. To minimise Z draw a line pa..
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If Mean value theorem is applicable, solve the equation Show that one of the roots lie in the open interval (a, b). This verifies the Mean Value Theore..
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Calcium Chloride balanced equation Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..
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The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell. K L M 2 8 2 ..
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steps for balancing redox equations by oxidation number method The skeleton equation is:..
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Ionization of Na ( g ) to Na + ( g ) In this step, energy equal to the ionisation energy of sodium is absorbed...
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Since the two decision variable x and y are non-negative, consider only the first quadrant of xy- plane Draw the line ax + by = c ...(1) For each constraint, the line (1) divides the first quadrant in to two regions say R 1 and R 2 , suppose (x 1 , 0) is..
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S configuration of optical isomers Priorities are assigned to the four different groups or atoms attached to the chiral carbon atom. One such rule is based on atomic numbers. An atom with higher atomic number gets higher priority. Foe e.g., in bromochloroiodomethane the sequence of priority is iodine, bromine, chlorine an..
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Separate the equation into two half reactions: The oxidation number of various atoms are shown below: In this case, chromium undergoes reduction, oxidation number decreases from +6 (in Cr 2 O ) to +3 (in Cr 3 + ) Fe 2 + (O.N. = +2) changes to Fe 3 + (O.N. = +3). The species underg..
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Find a value of the variable x for which the value of x 2 + 3x - 4 is equal to 0. Let x =1, Then, f(1) = (1) 2 + 3(1) - 4 = 0..
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