Step 2:
If log (sin C) comes out as positive, sin C would have to be greater than 1 and there is no solutio..
Step 2:
Form the combination (x 1 , x 2 , x 3 ) for the rows identified in step 1. Put x i if x i = 1 x i if x i = 0 For the 1 s t row, the expression is x 1 .x 2 .x 3 2 n d row, the expression is x 1 .x 2 .x 3 ' 3 r d row, t..
Step 3:
Assume that T r + 1 is the desired particular ter..
Step 4:
The Boolean function can be written as: f(x 1 , x 2 , x 3 ) = x 1 x 2 x 3 + x 1 x 2 x 3 ' + x 1 x 2 ' x 3 + x 1 ' x 2 ' x 3 ' Since the following is represented by a Boolean expression, it is a Boolean functio..
Step iv:
Express p 1 ,p 2 ,p 3 ...., Q in terms of p, q, ..
Step 5:
Put the value of r in the term T r + 1 . This gives the required particular term(s..
Step 4:
Multiply each frequency with corresponding deviation i.e., fd and obtain S f..
Step 5
The increase in oxidation number of 2 per atom can be balanced with decrease in oxidation number of 1 per atom if Zn atoms are multiplied by 1 and HCl by 2. The equation will be..
The increase in oxidation number of 2 per atom can be balanced with decrease in oxidation number of 1 per atom if Zn atoms are multiplied by 1 and HCl by 2. The equation will be..For Step Up Transformers
E s > E p i.e., K >1 N s > N..
Step 2:
We draw straight lines for the equation 2x+ y = 100 ...(2) x + y = 80 To determine two points on the straight line 2x + y = 100 Put y = 0, 2x = 100 x = 50 (50, 0) is a point on the line (2) put x = 0 in (2), y =100 (0, 100) is the other point on the line (2) Plotting these two poi..
We draw straight lines for the equation 2x+ y = 100 ...(2) x + y = 80 To determine two points on the straight line 2x + y = 100 Put y = 0, 2x = 100 x = 50 (50, 0) is a point on the line (2) put x = 0 in (2), y =100 (0, 100) is the other point on the line (2) Plotting these two poi.. Result
Pages   :     1     2     3     4     5     6     7     8     9     10     11
See what our Users say :
This tutor was excellent. very clear on all of the problems. I would like to have more tutoring from Tutor Vista
This Tutor Vista is GREAT! loved this session, it helped me heaps.
Incredible help, saved me from failing a test. Thank you so much. This tutoring is amazing! Explains things well, KUDOS - pam
The tutors are amazing. They are very committed in helping students solve the questions and explains all the steps beautifully. So 5 stars for Tutor Vista.
Looking for More Help!
