Step 1
Write oxidation number of each atom and split the equation into two half equations: In this reaction, zinc undergoes oxidation and NO 3 - undergoes reduction..
Write oxidation number of each atom and split the equation into two half equations: In this reaction, zinc undergoes oxidation and NO 3 - undergoes reduction..Step I:
Denote the statement involving natural numbers n = 1, 2,. by P(n..
Step 3:
Applying OR to all the combinations obtained in step 3, we have the expression x 1 x 2 x 3 + x 1 x 2 x 3 ' + x 1 x 2 ' x 3 + x 1 ' x 2 ' x ..
Step 3:
We have the following conditions on the variables x and y. a) Sum of the numbers is atleast 15 i.e., x + y 15 b) Difference of the numbers is at most 7 i.e., x - y 7 c) Since the x and y should be positive, we have two more conditions x > 0, y > 0 We call Z as objective function..
We have the following conditions on the variables x and y. a) Sum of the numbers is atleast 15 i.e., x + y 15 b) Difference of the numbers is at most 7 i.e., x - y 7 c) Since the x and y should be positive, we have two more conditions x > 0, y > 0 We call Z as objective function..Step 7
The molecular mass (or molar mass) is obtained either from the experimental data or from the vapor density of the compound by using the relationship, Molecular mass = 2 x Vapor dens..
Step iv:
Express p 1 ,p 2 ,p 3 ...., Q in terms of p, q, ..
Step 5
The increase in oxidation number of 2 per atom can be balanced with decrease in oxidation number of 1 per atom if Zn atoms are multiplied by 1 and HCl by 2. The equation will be..
The increase in oxidation number of 2 per atom can be balanced with decrease in oxidation number of 1 per atom if Zn atoms are multiplied by 1 and HCl by 2. The equation will be..Step vi:
If Q is true whenever p 1 ,p 2 ,p 3 .... are all true, then the argument p 1 , p 2 ,... Q is valid, otherwise it is invali..
If Q is true whenever p 1 ,p 2 ,p 3 .... are all true, then the argument p 1 , p 2 ,... Q is valid, otherwise it is invali..Step 3:
The oxidation number of copper has increased from 0 to +2 while that of nitrogen has decreased from +5 to ..
The oxidation number of copper has increased from 0 to +2 while that of nitrogen has decreased from +5 to ..Step 3
Catalytic oxidation of SO 2 to SO 3 . Catalyst - V 2 O 5 (Vanadium pentoxide) or platinum Temperature: 450 o C - 500 o C. Pressure: 760 - 1520 mm of Hg..
Catalytic oxidation of SO 2 to SO 3 . Catalyst - V 2 O 5 (Vanadium pentoxide) or platinum Temperature: 450 o C - 500 o C. Pressure: 760 - 1520 mm of Hg.. Result
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