Integration by Substitution
If u is a function of x, we can use the following formula to evaluate an integral. f dx = (f/(du/dx)) du Using the Formula Use of the formula is equivalent to the following procedure: 1. Write u as a function of x..
Substitution Method
Solve 2x - 9y = 0 (i) x - 18y = 27 (ii) From (i) 2x - 9y = 0 2x = 9y (iii) Substituting this value of x in (ii), we get, 9y - 36y = 54 - 27y = 54 y = -2 Substitute this value of y in (iii): = - ..
Solve 2x - 9y = 0 (i) x - 18y = 27 (ii) From (i) 2x - 9y = 0 2x = 9y (iii) Substituting this value of x in (ii), we get, 9y - 36y = 54 - 27y = 54 y = -2 Substitute this value of y in (iii): = - ..Solving Equations
Question 1 - Question: Which of the following equations have x=2, y=3 as solution ? (a) 8x-y = 12 (b) 2x+3y = 10 Answer: (a) Substitute x=2, y=3 in 8x-y=12 8(2)-3=12 16-3=12 x=2, y=3 is not a solution of 8x-y=12 (b) Substitute x=2, y=3 in 2x+3y=10 2(2)+3(3)=10 4+9=10 x=2, y=3 is..
Question 1 - Question: Which of the following equations have x=2, y=3 as solution ? (a) 8x-y = 12 (b) 2x+3y = 10 Answer: (a) Substitute x=2, y=3 in 8x-y=12 8(2)-3=12 16-3=12 x=2, y=3 is not a solution of 8x-y=12 (b) Substitute x=2, y=3 in 2x+3y=10 2(2)+3(3)=10 4+9=10 x=2, y=3 is..Methods to Solve Simultaneous Equations
Simultaneous Equations - Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, y = 0. Similar..
Simultaneous Equations - Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, y = 0. Similar..Solve (u - 34)(5u + 8)(15u - 7) = 0.
Solve ( u - 3 4 )(5 u + 8)( 1 5 u - 7) = 0. => 3 4 , 8 5 and 7 or 3 4 , - 8 5 and 35 or - 3 4 , 8 5 and 7 or 3 4 , 3 and - 35..
Solve 1f = 1u + 1v for u.
Solve 1 f = 1 u + 1 v for u . => u = f - v f v or u = - 1 f - 1 v or u = f + v f v or u = f v v - f..
Solve 1f = 1u + 1v for u.
Solve 1 f = 1 u + 1 v for u . => u = f - v f v or u = f + v f v or u = - 1 f - 1 v or u = f v v - f..
Solve the linear system by using the substitution method and find the ..
Solve the linear system by using the substitution method and find the number of solutions. 3 x + y = -10 6 x - 5 y = -55 => Infinitely many solutions or Exactly one solution or No solution or None of the above..
Solve the system by substitution: 4x - 2y = 6- 10x + 5y = - 15
Solve the system by substitution: 4 x - 2 y = 6 - 10 x + 5 y = - 15 => (2, 0) or (2, 3) or Infinite solutions or No solution..
Solve the system by substitution: 3x + 3y = 9,4x = - 4y + 8
Solve the system by substitution: 3 x + 3 y = 9, 4 x = - 4 y + 8 => No solution or (3, 9) or (2, 0) or (2, 1)..
Result
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