step 1 step 2 step 3 profit

The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Sh..

Concentration of CO 2 increases in bundle sheath cells. Rubisco acts as carboxylase enzyme. Calvin cycle starts and glucose is synthesised. Advantage of C 4 pathway- Photorespiration does not occur- Glucose is synthesized even when concentration of CO 2 is low. Molecules of ATP ..

Corresponding to each constant, we obtain a shaded region. The intersection of all these shaded regions is the feasible region or feasible solution of the LPP. Let us find the feasible solution for the problem of a decorative item dealer whose LPP is to maximise profit function. Z = 50x..

Multiply each fd by the corresponding d to get fd 2 and obtain S fd 2..

We have the following conditions on the variables x and y. a) Sum of the numbers is atleast 15 i.e., x + y 15 b) Difference of the numbers is at most 7 i.e., x - y 7 c) Since the x and y should be positive, we have two more conditions x > 0, y > 0 We call Z as objective function..

Separate the equation into two half reactions: The oxidation number of various atoms are shown below: In this case, chromium undergoes reduction, oxidation number decreases from +6 (in Cr 2 O ) to +3 (in Cr 3 + ) Fe 2 + (O.N. = +2) c..

Identify all rows of the table where the output is 1. Note that 1 s t , 2 n d , 3 r d and the last row has output 1..

Form the combination (x 1 , x 2 , x 3 ) for the rows identified in step 1. Put x i if x i = 1 x i if x i = 0 For the 1 s t row, the expression is x 1 .x 2 .x 3 2 n d row, the expr..

Divide x 2 + 3x -4 by (x-1), ..

Sulphur dioxide reacts with water to liberate nascent hydrogen. 2H 2 O(l) + SO 2 (g) -----------------> H 2 SO 4 (aq) + 2[H]water sulphur dioxide sulphuric acid nascent hydrog..