Step I :
Express the differential equation in the form f(x) dx = g(y) d..
Steps
- Carboxylation - Glycolytic reversal - Regeneration of RUBP Photorespiration Light dependent up take of O 2 by cells and release of CO 2 without producing ATP and NADPH. During high conc. of O 2 and high temperature. RUBISCO act as RUBP oxygenase. RUBP splits into PGA and phosphoglycolate...
- Carboxylation - Glycolytic reversal - Regeneration of RUBP Photorespiration Light dependent up take of O 2 by cells and release of CO 2 without producing ATP and NADPH. During high conc. of O 2 and high temperature. RUBISCO act as RUBP oxygenase. RUBP splits into PGA and phosphoglycolate...Steps
Write the symbols of the elements which form the compound. Below the symbol of each element write down its valency. Cross over the valencies of the atoms. ..
Write the symbols of the elements which form the compound. Below the symbol of each element write down its valency. Cross over the valencies of the atoms. ..First step
Sulphur dioxide reacts with water to liberate nascent hydrogen. 2H 2 O(l) + SO 2 (g) -----------------> H 2 SO 4 (aq) + 2[H]water sulphur dioxide sulphuric acid nascent hydrog..
Steps:
The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell. K L M 2 8 2 ..
Step 4:
Divide the total obtained in step 3 by the number of items and calculate the square root to get the standard deviatio..
Step 4:
Take the maximum and minimum values of f out of the values calculated in step 3. These will be the absolute maximum or absolute minimum value..
Step 2
Formation of chloride ion from chlorine atom in the gaseous phase. In this step energy equal to the electron affinity of chlorine is released...
Formation of chloride ion from chlorine atom in the gaseous phase. In this step energy equal to the electron affinity of chlorine is released...Step 3
Now add up the two half equations. Multiply equation (i) by 6 so that electrons are balanced. The balanced equation is: If we carefully see step 2 part-(iii) and (iv) we get a method for balancing redox reaction in acidic medium. Charge is balanced by ad..
Now add up the two half equations. Multiply equation (i) by 6 so that electrons are balanced. The balanced equation is: If we carefully see step 2 part-(iii) and (iv) we get a method for balancing redox reaction in acidic medium. Charge is balanced by ad..Step 5:
If (x 1 , y 1 ) is the point found in step 4, then x = x 1 , y = y 1 , is the optimal solution of the LPP and Z = ax 1 + by 1 is the optimal value. The above method of solving an LPP is more clear with the following exampl..
Result
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