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Steps
- Carboxylation - Glycolytic reversal - Regeneration of RUBP Photorespiration Light dependent up take of O 2 by cells and release of CO 2 without producing ATP and NADPH. During high conc. of O 2 and high temperature. RUBISCO act as RUBP oxygenase. RUBP splits into PGA and phosphoglycolate...
- Carboxylation - Glycolytic reversal - Regeneration of RUBP Photorespiration Light dependent up take of O 2 by cells and release of CO 2 without producing ATP and NADPH. During high conc. of O 2 and high temperature. RUBISCO act as RUBP oxygenase. RUBP splits into PGA and phosphoglycolate...Steps
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..Steps
Calculate empirical formula. Use vapor density if given. If molecular weight given, calculate 'n' using this formula. Molecular formula = n x empirical formul..
Calculate empirical formula. Use vapor density if given. If molecular weight given, calculate 'n' using this formula. Molecular formula = n x empirical formul..Step I
The two half-cell reactions are written in such a way that the reaction taking place at the left hand electrode is written as an oxidation reaction and that taking place at the right electrode is written as reduction reactio..
Steps:
The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell. K L M 2 8 2 ..
Step 4:
Take the maximum and minimum values of f out of the values calculated in step 3. These will be the absolute maximum or absolute minimum value..
Step 1
Ionization of Na ( g ) to Na + ( g ) In this step, energy equal to the ionisation energy of sodium is absorbed...
Ionization of Na ( g ) to Na + ( g ) In this step, energy equal to the ionisation energy of sodium is absorbed...Step 3
Formation of solid sodium chloride from Na + ( g ) and Cl - ( g ) . In this step, energy equal to the lattice energy is released. Total energy released per mole of NaCl formed = 776+349.4 kJ= 1125.4 kJ Total energy absorbed in step (1) = 495.8 kJ Therefore, Net energy ..
Formation of solid sodium chloride from Na + ( g ) and Cl - ( g ) . In this step, energy equal to the lattice energy is released. Total energy released per mole of NaCl formed = 776+349.4 kJ= 1125.4 kJ Total energy absorbed in step (1) = 495.8 kJ Therefore, Net energy ..Step 5:
If (x 1 , y 1 ) is the point found in step 4, then x = x 1 , y = y 1 , is the optimal solution of the LPP and Z = ax 1 + by 1 is the optimal value. The above method of solving an LPP is more clear with the following exampl..
Step 2:
Form the combination (x 1 , x 2 , x 3 ) for the rows identified in step 1. Put x i if x i = 1 x i if x i = 0 For the 1 s t row, the expression is x 1 .x 2 .x 3 2 n d row, the expression is x 1 .x 2 .x 3 ' 3 r d row, the expression is x 1 , x 2 '.x 3 Last row, the expression i..
Result
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