The sum of two negative integers is ______________.
The sum of two negative integers is ______________. => Positive or Negative or 0 or Cannot be determined..
Binomial Theorem Summary
of (a + b) n and is given by - If n is an odd natural number, then there are two middle terms in the expansion of (a + b)n and are given by i) The sum of all binomial coefficients in the expansion of (1+x) n is 2 n . ii) The sum of all even binomial coefficie..
of (a + b) n and is given by - If n is an odd natural number, then there are two middle terms in the expansion of (a + b)n and are given by i) The sum of all binomial coefficients in the expansion of (1+x) n is 2 n . ii) The sum of all even binomial coefficie..The average of 41 non-negative integers is 23.4. Find their sum.
The average of 41 non-negative integers is 23.4. Find their sum. => 918.4 or 960.4 or 959.4 or 958.4..
Definite Integral as a Limit of Sum
Definite Integral as a Limit of Sum - Let f be a continuous non-negative function defined on a closed interval [a, b]. Since the value of the function is non-negative, the graph of the function is a curve above X-axis. Let the graph of the curve be as shown in the figu..
Definite Integral as a Limit of Sum - Let f be a continuous non-negative function defined on a closed interval [a, b]. Since the value of the function is non-negative, the graph of the function is a curve above X-axis. Let the graph of the curve be as shown in the figu..The sum of two positive integers is ______________.
The sum of two positive integers is ______________. => Positive or Negative..
Factorising Trinomials
When the coefficient of the highest power is 1. i.e., ax 2 bx c, when a = 1 and b and c are integers. When two binomials are multiplied the product is a trinomial. Thus (x + 4) (x + 5) = x 2 + 9x + 20 (1) (x - 4) (x - 5) = x 2 - 9x + 20 (2) In this chapter we try to express ..
When the coefficient of the highest power is 1. i.e., ax 2 bx c, when a = 1 and b and c are integers. When two binomials are multiplied the product is a trinomial. Thus (x + 4) (x + 5) = x 2 + 9x + 20 (1) (x - 4) (x - 5) = x 2 - 9x + 20 (2) In this chapter we try to express ..Some Observations
For n N, in the expansion of (a + b) n , we observe that: the number of terms is n+1 the exponent of 'a' decreases from n to 0 the exponent of 'b' increases from 0 to n the sum of exponents of 'a' and 'b' in any term is n. the coefficient of any term is n C k where k is..
For n N, in the expansion of (a + b) n , we observe that: the number of terms is n+1 the exponent of 'a' decreases from n to 0 the exponent of 'b' increases from 0 to n the sum of exponents of 'a' and 'b' in any term is n. the coefficient of any term is n C k where k is..Summary of (a + b) n and is given by - If n is an odd natural number, then there are two middle terms in the expansion of (a + b)n and are given by i) The sum of all binomial coefficients in the expansion of (1+x) n is 2 n . ii) The sum of all even binomial coefficie..
of (a + b) n and is given by - If n is an odd natural number, then there are two middle terms in the expansion of (a + b)n and are given by i) The sum of all binomial coefficients in the expansion of (1+x) n is 2 n . ii) The sum of all even binomial coefficie..Complex Numbers
Square root of a negative number is known as an imaginary number . If x and y are real numbers, then x + iy is called a complex number . x is called the real part and y is called the imaginary part . The following are the types of complex numbers: Equality of Comple..
Online Algebra Help - Easy, affordable and fun
/content/math/number-theory/polynomials/polynomialsindex.php'>polynomials as the product of two or more polynomials is called factorisation. If A = B x C, B and C are called factors of A. Methods of Factorisation: (i) Common factors (ii) By expressing as difference of squares (iii) By grouping (iv)..
See what our Users say :
Very fast and clear. Made sure I understood the concepts instead of giving the answers to the problem.
Tutor helped me on every question and help me when i was confused. Thank you Tutor Vista
I think the tutors knew their stuff really well and was very helpful. math was actually something I dread.not anymore ,Thank you Tutor Vista - jennifer,New york
Tutor Vista tutors actually helped me to think through some of the problems instead of just doing them for me.Now i am more confident with math ,Thank you all
Looking for More Help!
