the specified key does not exist

. Glass is so presented/cited for it does not resist deformation very well. It softens rather than melts when heated and sags and flows on heating over a long period of ti..

Sid plans to expand the existing square flowerbed by quadrupling its dimensions. What sort of change does this expansion bring in the area of the square flowerbed? => The area decreases by 16 times. or The area doesn′t change. or The area increases by 16 times. or The area..

When the key K is pressed, current starts flowing through the coil P and this increases the magnetic flux linked with P. Since S is very close to P, the magnetic flux linked with S also increases. Thus induced emf, hence induced current is produced in S. The direction of induced current ..

Find the inverse of the matrix P = ( 3 6 5 10 ) if it exists. => ( 2 4 4 12 ) or ( 3 6 5 10 ) or ( 1 0 0 1 ) or does not exist...

The displacement s of a particle moving on a straight line at any time t is given by s = 8 t 2 + 6 t + 5. Find the instantaneous velocity of the particle at t = 4, if it exists. => 8 or 70 or 6 or Does not exist..

Which of the following is true for the function f ( x ) = x 2 + 4 at x = 0? I. f ( x ) is continuous at x = 0 II. f ( x ) is not continuous at x = 0 III. lim x → 0 f ( x ) = 2 IV. lim x → 0 f ( x ) does not exist => IV only or II, IV only or III, IV only or II only or ..

at x = 0 IV. g ( x ) is not differentiable at x = 0 V. g (0) does not exist => I, IV only or V only or II, III only or III, IV only..

If g(t ) = 6 7 t - 4 9 , then choose the correct one from the following. I. lim t → 7 - g ( t ) = ∞ II. lim t → 7 + g ( t ) = - ∞ III. lim t → 7 g ( t ) = ∞ IV. lim t → 7 g ( t ) = - ∞ V. lim t → 7 g(t ) does not exist. => I or IV..

If f(n ) = 5( 8 1 n ) + 9 , then choose the correct one from the following I. lim n → 0 - f ( n ) = ∞ II. lim n → 0 + f ( n ) = 9 III. lim n → 0 f ( n ) = 9 IV. lim n → 0 f ( n ) = 1 4 V. lim n → 0 f(n ) does not exist. => II or I or V or III or IV..

Which statement explains why the mean value theorem does not apply to the function f ( x ) = | x | x in the interval [-2, 2]? => there exists c ∈ [-2, 2] such that f ′ ( c ) = 0 or f ( x ) is differentiable in [-2, 2] or f ( x ) is not continu..