theorem 1

Theorem 1 - Parallelograms on the same base and between the same parallels are equal in area. ABCD and ABEF are two parallelograms on the same base AB and between the same parallels AB, DE area (ABCD) = area (ABEF) An alternate way of proving this theorem is as follows..

Theorem 1 - If a straight line meets another straight line, the adjacent angles so formed are supplementary. A straight line CO meets straight line AB at ..

Theorem 1 - If two sides of a triangle are equal, the angles opposite to them are equal. In AB = AC Draw AD, the bisector of to meet BC at ..

Parallelograms on the same base and between the same parallels are equal in area. ABCD and ABEF are two parallelograms on the same base AB and between the same parallels AB, DE area (ABCD) = area (ABEF) An alternate way of proving this theorem is as follows: Since both parallelograms are ..

To determine the incentre of a triangle, it is just sufficient to find the point of intersection of its two angles. The third angle bisector is bound to pass through it by virtue of the below theorem..

Statement - The locus of a point equidistant from two fixed points is the perpendicular bisector of the segment joining the two points. This theorem is proved in two parts. First prove that any point on the locus satisfies the conditi..

Let f be continuous on [a, b] and differentiable on the open interval (a, b). Then (a) f is increasing on [a, b] if f '(x) > 0 for each x (a, b) (b) f is decreasing on [a, b] if f '(x) < 0 for each x (a, b) This theorem can be proved by using Mean Value Theorem. We sh..

Theorem 1 - In a polygon of 'n' sides, the sum of the interior angles is equal to (2n - 4) right angles. ABCDE is an n sided polygon. The sum of the interior angles = (2n - 4) right angles Take any point O inside the polygon. Join OA, OB, O..

General solution of sin q = ..

In a polygon of 'n' sides, the sum of the interior angles is equal to (2n - 4) right angles. ABCDE is an n sided polygon. The sum of the interior angles = (2n - 4) right angles Take any point O inside the polygon. Join OA, OB, O..