Converse of Theorem4
If two diagonals of a parallelogram are equal, it is a rectangl..
Converse of Theorem 3
Statement - If a transversal intersects two lines in such a way that a pair of consecutive interior angles are supplementary, then the two lines are paralle..
Statement - If a transversal intersects two lines in such a way that a pair of consecutive interior angles are supplementary, then the two lines are paralle..Converse
Any point (or every point) on the perpendicular bisector of the line segment joining two given points is equidistant from them..
Any point (or every point) on the perpendicular bisector of the line segment joining two given points is equidistant from them..Converse of a Theorem
Converse of a Theorem is the transposition of a statement consisting of 'data' and 'to prove' 'Data' becomes 'To Prove' and 'To prove' becomes 'Data' in the converse theorem..
Converse of Mid-Point Theorem
The straight line drawn through the mid-point of one side of a triangle parallel to another, bisects the third sid..
Converse of Mid-Point Theorem
The straight line drawn through the mid-point of one side of a triangle parallel to another, bisects the third side. In ABC, P is the mid-point of AB and PQ || BC. AQ = CQ Draw CR || BA to meet PQ produced at ..
The straight line drawn through the mid-point of one side of a triangle parallel to another, bisects the third side. In ABC, P is the mid-point of AB and PQ || BC. AQ = CQ Draw CR || BA to meet PQ produced at ..Theorem
If two sides of a triangle are equal, the angles opposite to them are equa..
Theorem
If two lines intersect, then the vertically opposite angles are congruen..
Theorem:
The inverse of a square matrix if it exists, is unique. Let A be an invertible square matrix. If possible, let B and C be two inverse of A. Then AB = BA = I. AC = CA = I (by def. of inverse) Now, B = BI = B(AC) = (BA)C [ Matrix multiplication is associative] = IC = C i.e., B = C Hence t..
The inverse of a square matrix if it exists, is unique. Let A be an invertible square matrix. If possible, let B and C be two inverse of A. Then AB = BA = I. AC = CA = I (by def. of inverse) Now, B = BI = B(AC) = (BA)C [ Matrix multiplication is associative] = IC = C i.e., B = C Hence t..Theorem:
The number of circular permutations of n different objects is (n-1)..
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