|
Unlimited Tutoring & Homework Help
|
Some Trigonometrical Identities
1. sin A = cos (90 o - A). 2. sin A / cos a = tan A. 3. tan A x tan (90 o - A) = 1. 4. sin 2 A + cos 2 A = 1. 5. 1 + tan 2 A = sec 2 A. 6. 1 + cot 2 A = cosec 2 A. Where 'A' is the angl..
Some Trigonometrical Identities
1. sin A = cos (90 o - A) 2. 3. tan A x tan (90 o - A) = 1 4. sin 2 A + cos 2 A = 1 5. 1 + tan 2 A = sec 2 A 6. 1 + cot 2 A = cosec 2 A Let us prove the above identities. Let D ABC be a right-angled triangle with B = 90 o . Let BC = a, AC = b ..
1. sin A = cos (90 o - A) 2. 3. tan A x tan (90 o - A) = 1 4. sin 2 A + cos 2 A = 1 5. 1 + tan 2 A = sec 2 A 6. 1 + cot 2 A = cosec 2 A Let us prove the above identities. Let D ABC be a right-angled triangle with B = 90 o . Let BC = a, AC = b ..Trigonometrical Identities Introduction
Introduction - Let us recapitulate the trigonometric ratios (t-ratios). There are six t-ratios. D ABC is a right-angled triangle, B = 90 o . (i) In short, (ii) In shor..
Introduction - Let us recapitulate the trigonometric ratios (t-ratios). There are six t-ratios. D ABC is a right-angled triangle, B = 90 o . (i) In short, (ii) In shor..Trigonometrical Identities
Introduction - The trigonometric ratio's are: Sine, Cosine, Tangent, Cotangent, Secant, and Cosecan..
Conditional Trigonometric Identities
Conditional Trigonometric Identities - In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relat..
Conditional Trigonometric Identities - In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relat..Conditional Trigonometric Identities
In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relationship exists among the angles considered. Many interestin..
In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relationship exists among the angles considered. Many interestin..Trigonometric Functions
The circle whose radius is 1 unit whose centre is the origin of a rectangular co-ordinate system is called the unit circle. 1. cos q = x. 2. sin q = y. 3. tan q = y/x. 4. sec q = 1/x. 5. cosec q = 1/y. 6. cot q = x/y. The six functions of q defined by the above equation are..
Trigonometric ratios of Allied Angles
The following table shows the Trigonometric ratios of Allied Angles: - q 90- q 90 + q 180- q 180 + q 270- q 270 + q 2n P - q 2n P + q sin q -sin q cos q cos q sin q -sin q -cos q -cos q -sin q sin q cos q cos ..
Trigonometric ratios of Allied Angles
Trigonometric ratios of Allied Angles - The following results were proved earlier: 1) sin(- q ) = - sin q , cos(- q ) = cos q , tan(- q ) = - tan q..
Trigonometric ratios of Allied Angles - The following results were proved earlier: 1) sin(- q ) = - sin q , cos(- q ) = cos q , tan(- q ) = - tan q..Trigonometric ratios of Allied Angles
The following results were proved earlier: 1) sin(- q ) = - sin q , cos(- q ) = cos q , tan(- q ) = - tan q..
The following results were proved earlier: 1) sin(- q ) = - sin q , cos(- q ) = cos q , tan(- q ) = - tan q..See what our Users say :
Getting Home work help from online everyday helping me a lot to understand my math much better...
I am Jessica from New York, I got excellent English tutors from Tutor Vista, who helped me lot to overcome my grammar mistakes, Thanks a lot...
Chemistry is a tough subject for me, I get a great help here along with a detailed explanation from a virtual tutor, it's really amazing - Nancy
I asked a Math question in the chat box in tutorvista. I was amazed to see live response from the tutor who helped me with my questions. That was great. I joined their online regular tutoring so that I can get such help anytime. - Mary

