Step 1:
We have to choose two positive numbers. Let the two positive numbers be x and y. This x and y are decision variables..
Step 1:
Find a value of the variable x for which the value of x 2 + 3x - 4 is equal to 0. Let x =1, Then, f(1) = (1) 2 + 3(1) - 4 = 0..
Find a value of the variable x for which the value of x 2 + 3x - 4 is equal to 0. Let x =1, Then, f(1) = (1) 2 + 3(1) - 4 = 0..Step 1:
Since the two decision variable x and y are non-negative, consider only the first quadrant of xy- plane Draw the line ax + by = c ...(1) For each constraint, the line (1) divides the first quadrant in to two regions say R 1 and R 2 , suppose (x 1 , 0) is..
Since the two decision variable x and y are non-negative, consider only the first quadrant of xy- plane Draw the line ax + by = c ...(1) For each constraint, the line (1) divides the first quadrant in to two regions say R 1 and R 2 , suppose (x 1 , 0) is..Step 3:
We have the following conditions on the variables x and y. a) Sum of the numbers is atleast 15 i.e., x + y 15 b) Difference of the numbers is at most 7 i.e., x - y 7 c) Since the x and y should be positive, we have two more conditions x > 0, y > 0 We call Z as objectiv..
We have the following conditions on the variables x and y. a) Sum of the numbers is atleast 15 i.e., x + y 15 b) Difference of the numbers is at most 7 i.e., x - y 7 c) Since the x and y should be positive, we have two more conditions x > 0, y > 0 We call Z as objectiv..Step I
The two half-cell reactions are written in such a way that the reaction taking place at the left hand electrode is written as an oxidation reaction and that taking place at the right electrode is written as reduction reactio..
Steps:
The first 2 electrons will go to the 1 s t shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ). In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell..
Steps:
The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell. K ..
First step
Sulphur dioxide reacts with water to liberate nascent hydrogen. 2H 2 O(l) + SO 2 (g) -----------------> H 2 SO 4 (aq) + 2[H]water sulphur dioxide sulphuric acid nascent hydrog..
Steps
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..Steps
- Carboxylation - Glycolytic reversal - Regeneration of RUBP Photorespiration Light dependent up take of O 2 by cells and release of CO 2 without producing ATP and NADPH. During high conc. of O 2 and high temperature. RUBISCO act as RUBP oxygenase. RUBP splits ..
- Carboxylation - Glycolytic reversal - Regeneration of RUBP Photorespiration Light dependent up take of O 2 by cells and release of CO 2 without producing ATP and NADPH. During high conc. of O 2 and high temperature. RUBISCO act as RUBP oxygenase. RUBP splits .. Result
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