Definition of cosec
- 1 x For x R - (-1,1), if q is an angle whose cosecant is x, then we say that cosecant inverse of x is q and write cosec -1 x = q . In particular, if q [ -p/ 2, p /2] - {0}, then q is called the principal value of cosec -1 x. For ..
- 1 x For x R - (-1,1), if q is an angle whose cosecant is x, then we say that cosecant inverse of x is q and write cosec -1 x = q . In particular, if q [ -p/ 2, p /2] - {0}, then q is called the principal value of cosec -1 x. For ..Find the value of sec 20 - 3cosec 20.
Find the value of sec 20 - 3 cosec 20. => 0 or -4 or 1 or 4..
The value of the expression 3 cosec 20° - sec 20° is equal to ..
The value of the expression 3 cosec 20° - sec 20° is equal to _______ => 4 or 2 or 2 sin 2 0 ° sin 4 0 ° or 4 sin 2 0 ° sin 2 0 °..
The graph of the polar equation r = 4 cosec2θ cosθ is a
The graph of the polar equation r = 4 cosec 2 θ cos θ is a => circle or hyperbola or straight line or parabola or ellipse..
Find the points of horizontal tangency to the polar curve r = 5 cosec&..
Find the points of horizontal tangency to the polar curve r = 5 cosec θ + 1. => (6, π 2 ) and (4, 3 π 2 ) or (- 6, π 2 ) and (4, 3 π 2 ) or (- 6, π 2 ) and (- 4, 3 π 2 ) or (6, π 2 ) and (6, 3 π 2 ) or (6, π 2 ) and (- 4, 3 π 2 )..
Write the number of solutions of the equation sin 7x - cosec 7x = 0, i..
Write the number of solutions of the equation sin 7 x - cosec 7 x = 0, if 0° ≤ x ≤ 360°. => 3 or 2 or 0 or 1..
Which of the following is the horizontal asymptote of the curve f (x) ..
Which of the following is the horizontal asymptote of the curve f ( x ) = 4Arc cosec 4 x ? => y = π 4 or y = - π 2 or y = 0 or y = π..
If f (l) = 4cosec (cos 3l), then find f ′ (l).
If f ( l ) = 4cosec (cos 3 l ), then find f ′ ( l ). => 12 cosec(cos 3 l ) cot(cos 3 l ) or sin 3 l cosec(cos 3 l ) cot(cos 3 l ) or 12 cosec(cos 3 l ) cot(cos 3 l ) or - 12 sin 3 l cosec(cos 3 l ) cot(cos 3 l ) or 12 sin 3 l cosec(c..
If y = 34sec2x cosec2x, then find dydx.
If y = 34sec 2 x cosec 2 x , then find d y d x . => 34 (sec x tan x - cosec x cot x ) or 68 (sec x tan x - cosec x cot x ) or 68 (sec x tan x + cosec x cot x ) or 34 (sec x tan x + cosec x cot x )..
∫35(cosec 5x) dx =
∫ 35(cosec 5 x ) d x = => (ln ( cos 5 x cos 5 x + 1 ) ) + C or 7 2 (ln ( cos 5 x + 1 cos 5 x - 1 ) ) + C or (ln ( cos 5 x - 1 cos 5 x + 1 ) ..
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