What is the solution of the equation x + 9 = - 6?
What is the solution of the equation x + 9 = - 6? => 15 or 3 or - 3 or - 15..
Solution
[H 3 O + ] = 6.2 x 10 - 9 M pH = -log [H 3 O + ] pH = -log [6.2 x 10 - 9 ] = -(log 6.2 - 9 log 10) = -log 6.2 + 9 x 1 (log 6.2 = 0.79) = 9 - 0.79 = 8.21 8. Acid A, ..
Solution:
Initial velocity (u) = 0 Time taken (t) = 6 seconds Acceleration due to gravity (g) = 9.8 m/s 2 We make use of second equation of motion h = 0 + 4.9 x 36 h = 176.4 m 03. A stone projected vertically upward, takes 5 seconds to reach the highest point. ..
Initial velocity (u) = 0 Time taken (t) = 6 seconds Acceleration due to gravity (g) = 9.8 m/s 2 We make use of second equation of motion h = 0 + 4.9 x 36 h = 176.4 m 03. A stone projected vertically upward, takes 5 seconds to reach the highest point. ..Solution
The energy of a photon is given by E = h n where the frequency of light = 3.0 x 10 1 5 s - 1 Planck's constant, h = 6.63 x 10 - 3 4 J s E = (6.63 x 10 - 3 4 J s) x (3.0 x 10 1 5 s - 1 ) = 6.63 x 3 x 10 1 9 J = 1.99 x 10 -18 ..
Solution
The given reaction corresponds to, 6 F 1 mol 6 x 96,500 C 52 g (i) Then, 6 x 96,500 C produce 52 g Cr (ii) For 52 g of Cr one requires 6 x 96,500 C Then, 12.5 A x t = 16,701.9 ..
The given reaction corresponds to, 6 F 1 mol 6 x 96,500 C 52 g (i) Then, 6 x 96,500 C produce 52 g Cr (ii) For 52 g of Cr one requires 6 x 96,500 C Then, 12.5 A x t = 16,701.9 ..Solution
Formula mass of KNO 3 = (39 amu + 14 amu + 3 x 16 amu) = 101 amu Then, ..
Formula mass of KNO 3 = (39 amu + 14 amu + 3 x 16 amu) = 101 amu Then, ..Solution
1 pound force = 4.448 N, 1 inch = 2.54 x 10 - 2 m = 9.66 x 10 4 N m - 2 = 0.74 x 10 - 1 0 m 7.4 x 10 - 1 1 m 6. The density of ethanol is 0.79 g cm - 3 at 25 o C. What is its value in SI uni..
1 pound force = 4.448 N, 1 inch = 2.54 x 10 - 2 m = 9.66 x 10 4 N m - 2 = 0.74 x 10 - 1 0 m 7.4 x 10 - 1 1 m 6. The density of ethanol is 0.79 g cm - 3 at 25 o C. What is its value in SI uni..Suggested solution:
Let v be the speed acquired by the electron when accelerated by a potential difference of V. Then, (1/2) mv 2 = eV or v = 2eV/m The radius R of the circular path inside the magnetic field is mv 2 / R = BeV Given: B = 0.2 T, V = 3000 V, e = 1.6 x 10 1 9 c, m = 9..
Let v be the speed acquired by the electron when accelerated by a potential difference of V. Then, (1/2) mv 2 = eV or v = 2eV/m The radius R of the circular path inside the magnetic field is mv 2 / R = BeV Given: B = 0.2 T, V = 3000 V, e = 1.6 x 10 1 9 c, m = 9..Suggested solution:
For this case, when the alpha-particle is closest to the nucleus, it comes to rest and its initial kinetic energy is completely converted into potential energy. We assume that this takes place when the alpha particle is outside the nucleus. The condition is expressed by the relation where u i ..
For this case, when the alpha-particle is closest to the nucleus, it comes to rest and its initial kinetic energy is completely converted into potential energy. We assume that this takes place when the alpha particle is outside the nucleus. The condition is expressed by the relation where u i ..Salt solution Animation
Elements, Compounds and Mixtures..
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