which is a solution of the equation 2 + 2 = 14?


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Which is a solution of the equation 2x + 2 = 14?
Which is a solution of the equation 2 x + 2 = 14? => 6 or 8 or 10 or 4..
Approximate the solution of the linear equation 2.3(6 - 2x) = 1.8x - ..
Approximate the solution of the linear equation 2.3(6 - 2 x ) = 1.8 x - 14.5 by using a graphing calculator. => - 4.4 or - 7.4 or 4.4 or 0.3..
Purification of Colloidal Sols
Purification of Colloidal Sols - The colloidal solutions prepared by various methods usually contain electrolytes and other soluble substances as impurities. These impurities if not removed can destabilize the sols. Impurities are removed by the following methods: 1) D..
Solution
The longest continuous chain consists of four carbons. The two different side-chains are at equal distance from the two ends of the chain. Therefore, the numbering is done from the end closer to the carbon having more branching viz., The compound thus is named as 2,2,3..
Solution:
According to the equation, 207 + (14 +16 x 3) x 2 207 + (35.5 x 2) 207 + (14 + 48) x 2 207 + 71 207 + 62 x 2 278 207 + 124 331 g 278 g 331 g of lead nitrate yield 278 g of lead chloride. Hence, mass of lead chloride formed fro..
Solution:
Molecular weight of N 2 = 2 x 14 = 28 g28 g of N 2 at STP occupies = 22.4 L 2.8 g of N 2 at STP = ?28 g of N 2 = 22.4 L2.8g of N 2 = ? 2.8 g of N 2 at STP occupies a volume of 2.2..
Solution
1 means primary, 2 means secondary and 3 means tertiary carbon atom (i) 2-methyl-3-ethylhexane. (ii) 3,3,4-trimethylheptane (iii) 3-isopropylhexane..
Solution:
O 2 : SO 2 S : O 2 1 : 1 32 g : 1 vol. 22.4 : x y : 22.4 litres or 1 mole x = 22.4 litres y = 32 g Volume of SO 2 produced Mass of uncombined sulphur = 22.4 litres = 40 - 32 = 8..
Solution:
As per the equation, 64 64 + {14 + (16 x 3)} x 2 64 64 + (62 x 2 ) 64 64 + 124 64 188 64 g of copper gives 188 g of copper nitrate. Hence, mass of copper nitrate formed from 3.2 g of copper = ? Cu : Cu(NO 3 ) 2 64 g : 188 g 3.2..
Solution:
As per the equation, 2 (14 + 4 + 35.5) 2 vols.(of NH 3 ) 107 2 x 22.4 litres 107 g 44.8 litres or 44800 ml NH 4 Cl : NH 3 107 g : 44800 ml 2.675 g : x Volume of ammonia formed at STP = 1120 ml. Example: 31Calculate the volume of sulp..
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