Solution
= 0.05608 = 0.0561 The number of significant figures in the term 3.24 is 3, therefore the result should have 3 significant figures. Therefore, the correct answer is 0.0561. The number after zero is 8 and therefore it is rounded off to one. = 0.2615 x 10 - 4 = 0.3 x..
= 0.05608 = 0.0561 The number of significant figures in the term 3.24 is 3, therefore the result should have 3 significant figures. Therefore, the correct answer is 0.0561. The number after zero is 8 and therefore it is rounded off to one. = 0.2615 x 10 - 4 = 0.3 x..Solution
Let the concentration of NO be x mol litre -1 Therefore [NO] = 0.032 mole litre - 1 . 15. constants for the forward and backward reactions are found to be 4.2 x 10 -2 mol min -1 and 3.6 x 10 3 mol min -1 respectively. Calculate the equilib..
Let the concentration of NO be x mol litre -1 Therefore [NO] = 0.032 mole litre - 1 . 15. constants for the forward and backward reactions are found to be 4.2 x 10 -2 mol min -1 and 3.6 x 10 3 mol min -1 respectively. Calculate the equilib..Solution:
O 2 : SO 2 S : O 2 1 : 1 32 g : 1 vol. 22.4 : x y : 22.4 litres or 1 mole x = 22.4 litres y = 32 g Volume of SO 2 produced Mass of uncombined sulphur = 22.4 litres = 40 - 32 = 8..
O 2 : SO 2 S : O 2 1 : 1 32 g : 1 vol. 22.4 : x y : 22.4 litres or 1 mole x = 22.4 litres y = 32 g Volume of SO 2 produced Mass of uncombined sulphur = 22.4 litres = 40 - 32 = 8..Solution:
f (x) = x 3 - 6x 2 + 9x + 15 f ' (x) = 3x 2 -12x + 9 = 3(x 2 - 4x + 3) = 3 (x - 1) (x - 3) Thus x = 1 and x = 3 are the only points which cou..
f (x) = x 3 - 6x 2 + 9x + 15 f ' (x) = 3x 2 -12x + 9 = 3(x 2 - 4x + 3) = 3 (x - 1) (x - 3) Thus x = 1 and x = 3 are the only points which cou..Solution:
According to the problem Integrating, we have y = x 2 c This is the family of equations with parameter. The family of curves is represented by y = x 2 c, since one of these curves passes through (3,- 4), we have 4..
According to the problem Integrating, we have y = x 2 c This is the family of equations with parameter. The family of curves is represented by y = x 2 c, since one of these curves passes through (3,- 4), we have 4..Solution:
Let y = f (x) = x 1 / 4 Let x = 81, d x =1. Taking these values we have ..
Let y = f (x) = x 1 / 4 Let x = 81, d x =1. Taking these values we have ..Solution:
Since the tangent to the given curve is parallel to the line 4x - 2y + 5 = 0 Slope of the tangent = Slope of the given line ..
Since the tangent to the given curve is parallel to the line 4x - 2y + 5 = 0 Slope of the tangent = Slope of the given line ..Suggested solution:
The ratio of the length of the wires to the separation between them is large (more than 300). Therefore, one can estimate the approximate force on a section of either of the two wires (near their centres) by using the exact result for force per unit length for two infinitely long wires carrying cu..
The ratio of the length of the wires to the separation between them is large (more than 300). Therefore, one can estimate the approximate force on a section of either of the two wires (near their centres) by using the exact result for force per unit length for two infinitely long wires carrying cu..Suggested solution:
The electron revolving around the nucleus in a circular orbit is equivalent to a circular conductor carrying current. The current I, by definition I = Charge / Time = eV = 1.6 x 10 - 1 9 x 6.8 x 10 1 5 A = 1.1 x 10 - 3 A The magnetic..
Suggested solution:
Let R be the radius of the circular path described by the electron. Then mv 2 /R = B e v or R = mv/B e. Given: B = 0.019; G = 0.019 x 10 - 4 ; T = 1.9 x 10 - 6 T Therefore, R = 9.1 x 10 - 3 1 x 10 5 /1.9 x 10 - 6..
See what our Users say :
Their whiteboard is great. Online tutoring from this site is as good as like face to face tutoring and the great thing is I dont have to spend a lot.
I had Algebra assignment to be finished when I came across this site. I good great help finishing my assignment once I joined their service. Thanks !
I am a big fan of TutorVista tutoring. I am studying here from couple of months now and I want to continue for ever. - Ben
Very informative in such a short space. The structure of this site is practicle and can be easily understood. thanks - Craig
Looking for More Help!
