Solution
Let the concentration of NO be x mol litre -1 Therefore [NO] = 0.032 mole litre - 1 . 15. constants for the forward and backward reactions are found to be 4.2 x 10 -2 mol min -1 and 3.6 x 10 3 mol min -1 respectively. Calculate the equilib..
Let the concentration of NO be x mol litre -1 Therefore [NO] = 0.032 mole litre - 1 . 15. constants for the forward and backward reactions are found to be 4.2 x 10 -2 mol min -1 and 3.6 x 10 3 mol min -1 respectively. Calculate the equilib..Solution:
f (x) = x 3 - 6x 2 + 9x + 15 f ' (x) = 3x 2 -12x + 9 = 3(x 2 - 4x + 3) = 3 (x - 1) (x - 3) Thus x = 1 and x = 3 are the only points which cou..
f (x) = x 3 - 6x 2 + 9x + 15 f ' (x) = 3x 2 -12x + 9 = 3(x 2 - 4x + 3) = 3 (x - 1) (x - 3) Thus x = 1 and x = 3 are the only points which cou..Solution:
Let y = f (x) = x 1 / 4 Let x = 81, d x =1. Taking these values we have ..
Let y = f (x) = x 1 / 4 Let x = 81, d x =1. Taking these values we have ..Suggested solution:
The ratio of the length of the wires to the separation between them is large (more than 300). Therefore, one can estimate the approximate force on a section of either of the two wires (near their centres) by using the exact result for force per unit length for two infinitely long wires carrying cu..
The ratio of the length of the wires to the separation between them is large (more than 300). Therefore, one can estimate the approximate force on a section of either of the two wires (near their centres) by using the exact result for force per unit length for two infinitely long wires carrying cu..Suggested solution:
Let R be the radius of the circular path described by the electron. Then mv 2 /R = B e v or R = mv/B e. Given: B = 0.019; G = 0.019 x 10 - 4 ; T = 1.9 x 10 - 6 T Therefore, R = 9.1 x 10 - 3 1 x 10 5 /1.9 x 10 - 6..
Suggested solution:
For this case, when the alpha-particle is closest to the nucleus, it comes to rest and its initial kinetic energy is completely converted into potential energy. We assume that this takes place when the alpha particle is outside the nucleus. The condition is expressed by the relation where u i ..
For this case, when the alpha-particle is closest to the nucleus, it comes to rest and its initial kinetic energy is completely converted into potential energy. We assume that this takes place when the alpha particle is outside the nucleus. The condition is expressed by the relation where u i ..Solution
(i) 208.91 has five significant figures. (ii) 0.00456 has three significant figures. (iii) 453 has three significant figures. (iv) 2.945 x 10 4 has four significant figures. (v) 0.346 has three significant figures. 2. Express 0.00000345 in scientific notation and cal..
Solution
The given reaction corresponds to, 6 F 1 mol 6 x 96,500 C 52 g (i) Then, 6 x 96,500 C produce 52 g Cr (ii) For 52 g of Cr one requires 6 x 96,500 C Then, 12.5 A x t = 16,701.9 ..
The given reaction corresponds to, 6 F 1 mol 6 x 96,500 C 52 g (i) Then, 6 x 96,500 C produce 52 g Cr (ii) For 52 g of Cr one requires 6 x 96,500 C Then, 12.5 A x t = 16,701.9 ..Solution
W = - P (V 2 - V 1 ) = -3 x (5 - 3) = -6L.atm.= -6 x 101.25 J = 6.07 x 10 2 J Now, Q = m. C. D T Final temperatu..
W = - P (V 2 - V 1 ) = -3 x (5 - 3) = -6L.atm.= -6 x 101.25 J = 6.07 x 10 2 J Now, Q = m. C. D T Final temperatu..Solution
Nitrobenzene is reduced to aniline as follows: 123 g 6F (6 x 96,5000) So, if the current efficiency is 100%, then 6 x 96500 C of electricity would be required to reduce 123 g of nitrobenzene. Then, Quantity of electricity (at 50% efficiency) ..
Nitrobenzene is reduced to aniline as follows: 123 g 6F (6 x 96,5000) So, if the current efficiency is 100%, then 6 x 96500 C of electricity would be required to reduce 123 g of nitrobenzene. Then, Quantity of electricity (at 50% efficiency) ..See what our Users say :
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