which is a solution to the equation 6x + y = 4

The reaction is: Molecular mass of iodopropane (CH 3 CH 2 CH 2 I)= 3 x 12 + 7 x 1 + 127 = 170 Molecular mass of propene (CH 2 -CH=CH 2 ) = 3 x 12 + 6 x 1= 42 170 g of 1-iodopropane will give propene = 42 g But the actual yield is 36% so tha..

N 2 : NH 3 N 2 : H 2 1 : 2 1 : 3 200 : x 200: y x = 2 x 200 y= 200 x 3 x = 400 y = 600 Hence, volume of ammonia Hence, volume of hydrogen produced = 400 litres needed = 600 litres Volume of excess hydrogen = 1000..

f '(x) = 6x 2 - 42x + 36 f '(x) = 0 x = 1 and x = 6 are the critical values f ''(x) =12x - 42 If x =1, f ''(1) =12 - 42 = - 30 < 0 x =1 is a point of local maxima o..

Methane : Oxygen Methane : Steam Methane : Carbon dioxide 1 : 2 1 : 2 1 : 1 200 : x 200 : y 200 : z x= 2 x 200 y = 200 x 2 = 400 z = 200 x = 400 y = 400 Volume of oxygen Volume of steam Volume of carbondioxide used u..

Ca - 20; 2, 8, 8, 2Number of the valence shell - 4Therefore, sodium belongs to period 4 of the periodic tab..

The longest continuous chain consists of four carbons. The two different side-chains are at equal distance from the two ends of the chain. Therefore, the numbering is done from the end closer to the carbon having more branching viz., The compound thus is named as 2,2,3-trimethylbutane (c)..

Gram molecular mass of H 2 SO 4 = (2 x 1) + (1 x 32) + (4 x 16) = 98 g Mass of 1 mole of H 2 SO 4 = 98 g No. of grams of H 2 SO 4 present in 0.05 mole of it =? Mole : Mass 1 : 98 0.05 : x x = 0.05 x..

Mass of the reactants = 10gMass of the products = 4.4 + 5.6g = 10gSince the mass of the reactants is equal to the mass of the products, the observations are in agreement with the law of conservation of mas..

The above results are written as follows: So, The empirical formulae of the compound = C 1 H 4 or CH 4 The empirical formula mass = (1 x 12) + (4 x 1) = 12 + 4 = 16 amu Molecular mass (given) = 16 amu Therefore, Molecular formula = ..

As per the equation, 1 vol. 1 vol. + 2 vols. 1 vol. 3 vols. Volume of gaseous products obtained by burning 1 volume of CH 4 = 3vols. Volume of gaseous products obtained by burning 4.8 litres of CH 4 =? Methane : (carbon dioxide + water) 1 vol. : 3 vols. ..