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Solution:
Mass of 1 mole of CaSO 4 = 40 + 32 + (16 x 4) =40 + 32 + 64 = 136 ..
Mass of 1 mole of CaSO 4 = 40 + 32 + (16 x 4) =40 + 32 + 64 = 136 ..Solution:
Cl = 35.51 mole of a substance = 22.4 L1 Mole of a substance = 1 GMM1 GMM of Cl 2 = 71 g71 g of Cl 2 = 22.4 L7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 litr..
Cl = 35.51 mole of a substance = 22.4 L1 Mole of a substance = 1 GMM1 GMM of Cl 2 = 71 g71 g of Cl 2 = 22.4 L7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 litr..Solution
K w = 9.55 x 10 - 1 4 For water [H 3 O + ] = [OH - ] If, K w = [H 3 O + ] [OH - ] = 9.55 x 10 - 1 4 then, [H 3 O + ] [H 3 O + ] = 9.55 x 10 - 1 4 [H 3 O + ] 2 = 9.55 x 10 - 1 4 pH = -log [H 3 O + ] pH ..
K w = 9.55 x 10 - 1 4 For water [H 3 O + ] = [OH - ] If, K w = [H 3 O + ] [OH - ] = 9.55 x 10 - 1 4 then, [H 3 O + ] [H 3 O + ] = 9.55 x 10 - 1 4 [H 3 O + ] 2 = 9.55 x 10 - 1 4 pH = -log [H 3 O + ] pH ..Solution
Calculation of the percentages of different elements. Percentage of nitrogen can be calculated thus, Volume of H 2 SO 4 taken = 50 cm 3 N/4 of solution Volume of NaOH required for excess acid = 77 cm 3 N/10 of solution To calculate volume of N/..
Calculation of the percentages of different elements. Percentage of nitrogen can be calculated thus, Volume of H 2 SO 4 taken = 50 cm 3 N/4 of solution Volume of NaOH required for excess acid = 77 cm 3 N/10 of solution To calculate volume of N/..Solution
Magnesium allylide is an ionic carbide containing the C 3 4 - ions. It is called an allylide because on hydrolysis it gives allylene or propene..
Magnesium allylide is an ionic carbide containing the C 3 4 - ions. It is called an allylide because on hydrolysis it gives allylene or propene..Solution:
As per the equation, 64 g 1 volume (of SO 2 ) 64 g 22400 ml Volume of SO 2 formed using 64 g of copper = 22400 ml Volume of SO 2 formed using 4.8 g of copper = ? Cu : SO 2 64 g : 22400 ml 4.8 g : x Volume of sulphur dioxide formed at STP = 1680 m..
As per the equation, 64 g 1 volume (of SO 2 ) 64 g 22400 ml Volume of SO 2 formed using 64 g of copper = 22400 ml Volume of SO 2 formed using 4.8 g of copper = ? Cu : SO 2 64 g : 22400 ml 4.8 g : x Volume of sulphur dioxide formed at STP = 1680 m..Solution
Molecular weight of N 2 = 2 x 14 = 28 g 28 g of N 2 at STP occupies = 22.4L 2.8 g of N 2 at STP = ? 28 g of N 2 = 22.4L 2.8g of N 2 = ? 2.8 g of N 2 at STP occupies a volume of 2.24..
Molecular weight of N 2 = 2 x 14 = 28 g 28 g of N 2 at STP occupies = 22.4L 2.8 g of N 2 at STP = ? 28 g of N 2 = 22.4L 2.8g of N 2 = ? 2.8 g of N 2 at STP occupies a volume of 2.24..Solution
The energy of a photon is given by E = h n where the frequency of light = 3.0 x 10 1 5 s - 1 Planck's constant, h = 6.63 x 10 - 3 4 J s E = (6.63 x 10 - 3 4 J s) x (3.0 x 10 1 5 s - 1 ) = ..
Solution:
Mass (m) = 50 kg Momentum (p) = 225 kgm/s Velocity (v) = ? Velocity = 4.5 ..
Mass (m) = 50 kg Momentum (p) = 225 kgm/s Velocity (v) = ? Velocity = 4.5 ..Solution:
Molecular formula = SO 2 Molecular weight = 1 x 32 + 2 x 16 = 64 g64g of SO 2 occupies 22.4 L32 g of SO 2 = ? Volume of 32 g of SO 2 is 11.2 litr..
Molecular formula = SO 2 Molecular weight = 1 x 32 + 2 x 16 = 64 g64g of SO 2 occupies 22.4 L32 g of SO 2 = ? Volume of 32 g of SO 2 is 11.2 litr..See what our Users say :
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