Solution
pH = 7.4= -log[H + ] log[H + ]= -7.4 = 8.6 [H + ]= 3.98 x 10 - 8 4 x 10 - 8 M ..
pH = 7.4= -log[H + ] log[H + ]= -7.4 = 8.6 [H + ]= 3.98 x 10 - 8 4 x 10 - 8 M ..Solution
Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise ..
Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise ..Solution
The problem is done in steps: Calculation of the percentage of chlorine: We know that, Cl = AgCl 35.5g (108 +35.5)= 143.5? 5 mg Then, Percentage of chlorine in the sample = Empirical formula = C 3 H 2 Cl Empirical formula mass = (3 x 12 amu + 1 amu + 1 x 35.5 amu) = 73.5..
The problem is done in steps: Calculation of the percentage of chlorine: We know that, Cl = AgCl 35.5g (108 +35.5)= 143.5? 5 mg Then, Percentage of chlorine in the sample = Empirical formula = C 3 H 2 Cl Empirical formula mass = (3 x 12 amu + 1 amu + 1 x 35.5 amu) = 73.5..Solution:
200 mL of CO 2 = 0.40 g 22.4 L of CO 2 = 12 + 32 (44g) Molecular weight = 2 x vapor density = 2 x 22.22 = 44..
200 mL of CO 2 = 0.40 g 22.4 L of CO 2 = 12 + 32 (44g) Molecular weight = 2 x vapor density = 2 x 22.22 = 44..Solution
The possible structures for the carboxylic acid are: 3. Write structural formulas for all the isomeric amines with molecular formula C 4 H 1 1 ..
The possible structures for the carboxylic acid are: 3. Write structural formulas for all the isomeric amines with molecular formula C 4 H 1 1 ..Solution:
0 - 8 : 2, 6Valency = 8 - Number of valence electrons= 8 - 6= 2 If the outermost shell of an atom is completely filled, its valency = 0. The outermost shells of the noble gases helium, neon, argon, krypton etc. are completely filled. Hence their valency is zero. Such elements ar..
0 - 8 : 2, 6Valency = 8 - Number of valence electrons= 8 - 6= 2 If the outermost shell of an atom is completely filled, its valency = 0. The outermost shells of the noble gases helium, neon, argon, krypton etc. are completely filled. Hence their valency is zero. Such elements ar..Solution
According to the equation, if 2 moles of SO 3 are formed, 2 moles of SO 2 and 1 mole of O 2 are used up. Hence 1.6 moles of SO3 are formed from 1.6 moles of SO 2 and 0.8 mole of O 2 . Therefore, SO 2 left over at equilibrium = 2 - 1.6 = 0.4 ..
According to the equation, if 2 moles of SO 3 are formed, 2 moles of SO 2 and 1 mole of O 2 are used up. Hence 1.6 moles of SO3 are formed from 1.6 moles of SO 2 and 0.8 mole of O 2 . Therefore, SO 2 left over at equilibrium = 2 - 1.6 = 0.4 ..Solution
SO 2 Here all atoms obey the octet rule. Oxygen and sulphur atoms have six electrons in their outermost shells. The Lewis structure of SO 2 is, S is attached to one O atom through a double bond while to the other O atom through a coordinate bond. All atoms have eight electrons in thei..
SO 2 Here all atoms obey the octet rule. Oxygen and sulphur atoms have six electrons in their outermost shells. The Lewis structure of SO 2 is, S is attached to one O atom through a double bond while to the other O atom through a coordinate bond. All atoms have eight electrons in thei..Solution:
a. 360 cm 3 of N 2 = 0.45g 22.4L of gas = 1 gram molecular weight 22.4L = 22,400 cm 3 . (1L = 1000 cm 3 ) 360 cm 3 of N 2 = 0.45g 22,400 cm 3 of N 2 = ? Gram molecular weight of N 2 is 28 g. b. 308 cm 3 Cl 2 = 0.979 g 22.400 cm 3 of Cl 2 = ? Molecular weight of C..
a. 360 cm 3 of N 2 = 0.45g 22.4L of gas = 1 gram molecular weight 22.4L = 22,400 cm 3 . (1L = 1000 cm 3 ) 360 cm 3 of N 2 = 0.45g 22,400 cm 3 of N 2 = ? Gram molecular weight of N 2 is 28 g. b. 308 cm 3 Cl 2 = 0.979 g 22.400 cm 3 of Cl 2 = ? Molecular weight of C..Solution
Suppose x be the oxidation number of the underlined atom: 10. Calculate the oxidation number of (i) Fe in Fe 3 O 4 (ii) S in Na 2 S 4 O 6 ..
Suppose x be the oxidation number of the underlined atom: 10. Calculate the oxidation number of (i) Fe in Fe 3 O 4 (ii) S in Na 2 S 4 O 6 ..See what our Users say :
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