which is a solution to the equation 6x y %3d 4

pH = 7.4= -log[H + ] log[H + ]= -7.4 = 8.6 [H + ]= 3.98 x 10 - 8 4 x 10 - 8 M ..

Mass of the organic compound taken = 0.244 g Mass of CO 2 formed = 0.616 g Mass of H 2 O formed = 0.108 g We know that CO 2 = C and H 2 O = 2H44 g 12 g 18 g 2g (iii) Percentage of O in the compound = 100 - (68.85 + 4.92) = 26.23 The percentage composition of the compoun..

200 mL of CO 2 = 0.40 g 22.4 L of CO 2 = 12 + 32 (44g) Molecular weight = 2 x vapor density = 2 x 22.22 = 44..

The possible structures for the carboxylic acid are: 3. Write structural formulas for all the isomeric amines with molecular formula C 4 H 1 1 ..

Molecular formula = SO 2 Molecular weight = 1 x 32 + 2 x 16 = 64g 64g of SO 2 occupies 22.4L 32 g of SO 2 = ? Volume of 32 g of SO 2 is 11.2 lite..

Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise ..

According to the equation, if 2 moles of SO 3 are formed, 2 moles of SO 2 and 1 mole of O 2 are used up. Hence 1.6 moles of SO3 are formed from 1.6 moles of SO 2 and 0.8 mole of O 2 . Therefore, SO 2 left over at equilibrium = 2 - 1.6 = 0.4 ..

The given problem is solved in the following table. Empirical formula = N 2 H 8 S 1 O 4 = N 2 H 8 SO 4..

SO 2 Here all atoms obey the octet rule. Oxygen and sulphur atoms have six electrons in their outermost shells. The Lewis structure of SO 2 is, S is attached to one O atom through a double bond while to the other O atom through a coordinate bond. All atoms have eight electrons in thei..

a. 360 cm 3 of N 2 = 0.45g22.4L of gas = 1 gram molecular weight22.4L = 22,400 cm 3 . (1L = 1000 cm 3 )360 cm 3 of N 2 = 0.45g22,400 cm 3 of N 2 = ? Gram molecular weight of N 2 is 28 g.b. 308 cm 3 Cl 2 = 0.979 g22.400 cm 3 of Cl 2 = ? Molecular weight of Cl 2 = 71...