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Which of the following is the particular solution for the given differ..
Which of the following is the particular solution for the given differential equation (5 - 2 x ) y = d y d x , given that y = 2 w..
Which of the following is the particular solution for the given differ..
Which of the following is the particular solution for the given differential equation d y d x = 2 x + 1 y - 3 given that y = 4 when x = 0? ..
Which of the following is the particular solution for the given diffe..
Which of the following is the particular solution for the given differential equation d y d x + 2 x = 3 x 2 such that y = 2 when x..
Which of the following is the particular solution for the given differ..
Which of the following is the particular solution for the given differential equation d y d x = x ² y such that y = 3 when x = 0? => y..
Enthalpy of solution (DHsol)
When a solute is dissolved in a solvent a solution is formed. During dissolution of a solute in any solvent, a certain amount of heat is either absorbed or evolved. Such heat changes under constant pressure conditions are known as the enthalpy of solution. '..
Which of the following is the graphical solution and slope field for t..
Which of the following is the graphical solution and slope field for the differential equation d y d x = sin x ? => Graph - 2 or Graph - 1 or Graph - 3 or Graph - 5 or Graph - 4..
Solution
We know that, pK a = -log K a or K a = 10 - p K a Therefore, for the given acids, K a (A) = 10 - 1 . 5 K a (B) = 10 - 3 . 5 K a (C) = 10 - 2 . 0 K a (D) = 10 - 5 . 0 Since, 10 - 5..
Which of the following is the slope field for the differential equatio..
Which of the following is the slope field for the differential equation d y d x = x ? => Graph - 4 or Graph - 1 or Graph - 3 or Graph - 2 or Graph - 5..
Solution
[H 3 O + ] = 6.2 x 10 - 9 M pH = -log [H 3 O + ] pH = -log [6.2 x 10 - 9 ] = -(log 6.2 - 9 log 10) = -log 6.2 + 9 x 1 (log 6.2 = 0.79) = 9 - 0.79 = 8.21 8. Acid A, B, C and D..
Solution
The volume of H 2 SO 4 neutralised by N/10 NaOH can be obtained as follows: N a c i d x V a c i d = N a l k a l i x V a l k a l i Therefore, Volume of N/5 H 2 SO 4 used for neutralizing NH 3..
The volume of H 2 SO 4 neutralised by N/10 NaOH can be obtained as follows: N a c i d x V a c i d = N a l k a l i x V a l k a l i Therefore, Volume of N/5 H 2 SO 4 used for neutralizing NH 3.. Result
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