Which of the following is the solution of the equation M - 9 = - 5?
Which of the following is the solution of the equation M - 9 = - 5? => 4 or 6 or -0 or -4..
Solution
[H 3 O + ] = 6.2 x 10 - 9 M pH = -log [H 3 O + ] pH = -log [6.2 x 10 - 9 ] = -(log 6.2 - 9 log 10) = -log 6.2 + 9 x 1 (log 6.2 = 0.79) = 9 - 0.79 = 8.21 8. Acid A, B, C and D have the following pKa values..
Solution
Equilibrium constant for the two reactions may be written as follows and From above, we have The values of K 1 and K 2 show that the value of equilibrium constant for a reaction depends upon the stoichiometry of the chemical equation for the reaction. 9. At 70..
Equilibrium constant for the two reactions may be written as follows and From above, we have The values of K 1 and K 2 show that the value of equilibrium constant for a reaction depends upon the stoichiometry of the chemical equation for the reaction. 9. At 70..The population of a state is four hundred five million, eight thousand..
The population of a state is four hundred five million, eight thousand nine. Which of the following represents this number in the standard form? => 405,008,900 or 405,008,009 or 405,080,009 or 405,008,090..
Purification of Colloidal Sols
Purification of Colloidal Sols - The colloidal solutions prepared by various methods usually contain electrolytes and other soluble substances as impurities. These impurities if not removed can destabilize the sols. Impurities are removed by the following met..
Solution
Phosphorus atom has five electrons in its outermost shell. It needs three more electrons to complete its shell. One electron is required to complete a chlorine atom, as its outer shell has seven electrons. Thus, one phosphorus atom can share one electron pair with each of the three chlor..
Phosphorus atom has five electrons in its outermost shell. It needs three more electrons to complete its shell. One electron is required to complete a chlorine atom, as its outer shell has seven electrons. Thus, one phosphorus atom can share one electron pair with each of the three chlor..Solution:
In 100g of the compound, masses of elements are as follows: In 100 grams of compound, 71.8 g are antimony and 28.2% sulphur. Empirical formula is Sb 2 S ..
In 100g of the compound, masses of elements are as follows: In 100 grams of compound, 71.8 g are antimony and 28.2% sulphur. Empirical formula is Sb 2 S ..Solution
In a beryllium chloride molecule represented by the type AB 2 , the central atom A has two electron pairs located on either side of it, the molecule AB 2 takes a linear geometry...
In a beryllium chloride molecule represented by the type AB 2 , the central atom A has two electron pairs located on either side of it, the molecule AB 2 takes a linear geometry...Solution
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound Hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% In the first compound the number of parts of oxygen that combine with one part by mass of hydrogen In the second compound the number of p..
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound Hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% In the first compound the number of parts of oxygen that combine with one part by mass of hydrogen In the second compound the number of p..Solution:
Time taken = 5 seconds Final velocity (v) = 0 (at maximum height velocity will be equal to zero) v = u + gt 0 = u - 9.8 x 5 0 = u - 49.0 u = 49 m/s Initial velocity = 49 m..
Time taken = 5 seconds Final velocity (v) = 0 (at maximum height velocity will be equal to zero) v = u + gt 0 = u - 9.8 x 5 0 = u - 49.0 u = 49 m/s Initial velocity = 49 m..See what our Users say :
Better than great. That was the best 45 minutes i have spent on here. We got a lot done and i have a better understanding of the material. Thanks
Tutors here are the best and Tutor Vista you are the best online tutoring company - Sam
The tutors are amazing. They are very committed in helping students solve the questions and explains all the steps beautifully. So 5 stars for Tutor Vista.
Looking for More Help!
