Which of the following is the solution of the equation M - 9 = - 5?
Which of the following is the solution of the equation M - 9 = - 5? => 4 or 6 or -0 or -4..
Solution
We know that, pK a = -log K a or K a = 10 - p K a Therefore, for the given acids, K a (A) = 10 - 1 . 5 K a (B) = 10 - 3 . 5 K a (C) = 10 - 2 . 0 K a (D) = 10 - 5 . 0 Since, 10 - 5 . 0 < 10 - 3 . ..
Which of the following choices is the solution of the equation M - 13 ..
Which of the following choices is the solution of the equation M - 13 = - 4? => - 5 or 9 or 11 or - 9..
Purification of Colloidal Sols
The colloidal solutions prepared by various methods usually contain electrolytes and other soluble substances as impurities. These impurities if not removed can destabilize the sols. Impurities are removed by the following methods: 1) Dialysis 2) Ultra-filtration 3) Ul..
Solution:
In 100g of the compound, masses of elements are as follows: In 100 grams of compound, 71.8 g are antimony and 28.2% sulphur. Empirical formula is Sb 2 S ..
In 100g of the compound, masses of elements are as follows: In 100 grams of compound, 71.8 g are antimony and 28.2% sulphur. Empirical formula is Sb 2 S ..Solution
In a beryllium chloride molecule represented by the type AB 2 , the central atom A has two electron pairs located on either side of it, the molecule AB 2 takes a linear geometry...
In a beryllium chloride molecule represented by the type AB 2 , the central atom A has two electron pairs located on either side of it, the molecule AB 2 takes a linear geometry...Solution:
1 GMM = 6.023 x 10 2 3 molecules 23 + 35.5 g = 58.5g = 1 GMM of NaCl 58.5g = 6.023 x 10 2 3 molecules 500g = ? The number of molecules in 500g of sodium chloride is 34.2 x 6.023 x 2 3 molecul..
1 GMM = 6.023 x 10 2 3 molecules 23 + 35.5 g = 58.5g = 1 GMM of NaCl 58.5g = 6.023 x 10 2 3 molecules 500g = ? The number of molecules in 500g of sodium chloride is 34.2 x 6.023 x 2 3 molecul..Solution:
Time taken = 5 seconds Final velocity (v) = 0 (at maximum height velocity will be equal to zero) v = u + gt 0 = u - 9.8 x 5 0 = u - 49.0 u = 49 m/s Initial velocity = 49 m..
Time taken = 5 seconds Final velocity (v) = 0 (at maximum height velocity will be equal to zero) v = u + gt 0 = u - 9.8 x 5 0 = u - 49.0 u = 49 m/s Initial velocity = 49 m..Solution:
Cl = 35.5 1 mole of a substance = 22.4L 1 Mole of a substance = 1 GMM 1 GMM of Cl 2 = 71 g 71 g of Cl 2 = 22.4 L 7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 lite..
Cl = 35.5 1 mole of a substance = 22.4L 1 Mole of a substance = 1 GMM 1 GMM of Cl 2 = 71 g 71 g of Cl 2 = 22.4 L 7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 lite..Solution:
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% Ratio of the masses of oxygen that combine with fixed mass of hydrogen 15.86: 7.9 or 2:1 The ratio illustrates the law of mul..
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% Ratio of the masses of oxygen that combine with fixed mass of hydrogen 15.86: 7.9 or 2:1 The ratio illustrates the law of mul.. Result
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