Geometry mainly deals with shapes. In basic geometry the preliminary concepts line point, line, planes, angles, parallel and perpendicular some basic shapes are covered.

Real life application of geometry is widely seen in computing perimeter, area of places, distances, volumes of 3 dimensional figures (containers ,swimming pools etc).

Point

Line, line segment

Ray

Planes

Angles :

Types of angles (Acute, obtuse,right)

Angles in Polygons

Angles in parallel lines (cut by transversal)

Names of different shapes based on number of sides

Regular and irregular polygons

Angles in a polygon

Types of triangles :Triangles are classified based on the angles and sides. Types of triangles based on angles are acute triangle, right triangle and obtuse triangle.

Types of triangles based on the sides are equilateral triangles, isosceles triangle and scalene triangle.

Properties of triangle

Altitude, median of triangle

Similar triangles (Proofs )

Congruent Triangles

Types of quadrilaterals based on the sides and angles .

Square (all sides and angles are equal).

Rectangle (all angles are right angles and opposite sides are equal)

Parallelogram(Opposite sides and opposite angles are equal)

Trapezoid (One pair of opposite sides is parallel)

Rhombus

Kite

Diagonals of a quadrilateral

In advanced level , properties of secant and tangents .intercepted arc, intersection of two circles, apothem will be discussed.

Proofs related to similar figures.

Properties of similar figures.

Proofs for Congruent figures

Theorems related to congruent triangles.

Real life application of concept in word problems

Area of composite shapes

Area of regular Polygon

Area of irregular polygons

Introduction to Pyramids . Prisms ,cylinders and cone

Number of vertices, edges and face of 3-D shapes

Surface area ,lateral surface area

Total surface area of a prism = (perimeter of base)Xheight + 2area of base

Total surface area of Prism = $\frac{1}{2}$ (perimeter of base) X height + area of base

Lateral surface area of Prism= perimeter of base X height

Lateral surface area of Pyramid = $\frac{1}{2}$ perimeter of base X slant height

Volume of a 3 D object

Volume of prisms = Area of base X height

Volume of pyramids = $\frac{1}{3}$ Area of base X height

Volume of sphere = $\frac{4}{3}$ $\pi r^2$

Volume of composite figures (Ex : Cylinder topped with hemisphere)

Proof

Special right triangles

Application of Pythagorean theorem to solve right triangles.

1. Identify the acute angle from given angles.

Solution:

Solution:

2. Find the area of a Circle with radius of 10 cm. Take $\pi$ = 3.14. Round up the answer to nearest tenth.

Solution: Area of a circle= p$r^2$

= 3.14$(10)^2$

= 314 sq cm.

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